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(2y-x)的五次方等于多少?

(2y)^5-5*(2y)^4*x+10*(2y)^3*x^2-10*(2y)^2*x^3+5*(2y)*x^4-x^5

(x-2y)的5次方/(2y-x)的3次方 =-(2y-x)的5次方/(2y-x)的3次方 =-(2y-x)的2次方

(x-2y)^5的展开式中,x³y²的系数 =(5C3)(-2)^2 =10(4) =40

【参考答案】 原式=[(x-2y)^10]÷[-(x-2y)^5]÷[(x-2y)^4] =-(x-2y)^(10-5-4) =-(x-2y) =2y-x 满意敬请采纳,不理解欢迎追问

原式=(x-2y)²*[-(x-2y)]^5 =(x-2y)²*[-(x-2y)^5] =-(x-2y)^7

题干信息不全

y的导数减(2y/x)=x的二分之五次方的通解 y'-(2y/x)=x^(5/2) 常数变易法 先求:y'-(2y/x)=0的通解 dy/dx=2y/x (1/y)dy=(2/x)dx 两边积分: ln|y|=2ln|x|+lnC ln|y|=ln(Cx^2) |y|=Cx^2 y=C1x^2 (C1=±C) 设y'-(2y/x)=x^(5/2)的通解: y=u(x)x^2 y'...

解:原式=2x(2y-x)(2y+x)(2y+x)/(x-2y)(x+2y)²=-2x

2(x-2y)²-7(x+2y)³-3(2y-x)²+5(x+2y)³ =2(x-2y)²-7(x+2y)³-3(x-2y)²+5(x+2y)³ =-(x-2y)²-2(x+2y)³

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